ESTADISTICA PARA INGENIEROS WILLIAM NAVIDI PDF

Embed Size px x x x x Chapter 1. Chapter 2. Chapter 3. Chapter 5. Chapter 7.

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Embed Size px x x x x Chapter 1. Chapter 2. Chapter 3. Chapter 5. Chapter 7. Chapter 8. Chapter 9. Chapter It is conceptual. What is important is the population proportion of defectives; the sample proportion is only an approx-imation. The population proportion for the new process may in fact be greater or less than that of the oldprocess. The population proportion for the new process may be 0. The total number of points scored in the class of 30 students is 30 72 The total number of pointsscored in the class of 40 students is 40 79 The total number of points scored in both classes combinedis There are 30 40 70 students in both classes combined.

Therefore the mean scorefor the two classes combined is 70 The tertiles have cutpoints 1 3 17 5 67 and 2 3 17 11 The first tertileis therefore the average of the sample values in positions 5 and 6, which is 44 46 2 The second tertileis the average of the sample values in positions 11 and 12, which is 76 79 2 77 5.

The quintiles have cutpoints i 5 17 for i 1 2 3 4. The quintiles are thereforethe averages of the sample values in positions 3 and 4, in positions 6 and 7, in positions 10 and 11, and inpositions 13 and The quintiles are therefore 23 41 2 32, 46 49 2 47 5, 74 76 2 75, and 82 89 2 85 5. There are 23 stems in this plot. An advantage of this plot over the one in Figure 1. A disadvantage is that there are too many stems, and many ofthem are empty. The measurements in Group 1 are notfar from symmetric, although the boxplot suggests a slight skew to the left since the median is closer to the thirdquartile than the first.

There are no outliers. Most of the measurements for Group 2 are highly concentrated ina narrow range, and skewed to the left within that range.

The remaining four measurements are outliers. This sum is approx-imately 0 12 0 0 0 02 0 0 0 Therefore there are more women in the interval mm. Any point more than 1. To find the IQR, arrange the values in order: 4, 10, 20, 25, 31, 36, 37, 41, 44, 68, There aren 11 values. The first quartile is the value in position 0 25 n 1 3, which is The third quartile is thevalue in position 0 75 n 1 9, which is The interquartile range is 44 20 There are no points less than 20 36 16, so there are no outliers on the low side.

There isone point, 82, that is greater than 44 36 Therefore 82 is the only outlier. The figure on the left is a sketch of separate histograms for each group. The histogram on the right is a sketchof a histogram for the two groups combined. There is more spread in the combined histogram than in either ofthe separate ones. Therefore the standard deviation of all heights is greater than 2.

The answer is ii. The minimum value of 2 is an outlier, since it is more than 1. The lower whisker should extend to the smallest point that is not an outlier, but the value ofthis point is not given.

Post on Dec 1. Category: Documents 18 download. It is tangible. A good knowledge of the process that generated the data. False 3. The sample size can be any odd number. If all the numbers in the list are the same, the standard deviation will equal 0. Other choices for the endpoints are possible. Stem Leaf1 10 3 There are 23 stems in this plot. Supplementary Exercises for Chapter 1 1. If the result differs greatly fro.

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